/*
String indexOf() and lastIndexOf() functions
Examples of how to evaluate, look for, and replace characters in a String
created 27 Jul 2010
modified 2 Apr 2012
by Tom Igoe
This example code is in the public domain.
http://www.arduino.cc/en/Tutorial/StringIndexOf
*/
void setup() {
// Open serial communications and wait for port to open:
Serial.begin(9600);
while (!Serial) {
; // wait for serial port to connect. Needed for native USB port only
}
// send an intro:
Serial.println("\n\nString indexOf() and lastIndexOf() functions:");
Serial.println();
}
void loop() {
// indexOf() returns the position (i.e. index) of a particular character in a
// String. For example, if you were parsing HTML tags, you could use it:
String stringOne = "";
int firstClosingBracket = stringOne.indexOf('>');
Serial.println("The index of > in the string " + stringOne + " is " + firstClosingBracket);
stringOne = "";
int secondOpeningBracket = firstClosingBracket + 1;
int secondClosingBracket = stringOne.indexOf('>', secondOpeningBracket);
Serial.println("The index of the second > in the string " + stringOne + " is " + secondClosingBracket);
// you can also use indexOf() to search for Strings:
stringOne = "";
int bodyTag = stringOne.indexOf("");
Serial.println("The index of the body tag in the string " + stringOne + " is " + bodyTag);
stringOne = "";
int firstListItem = stringOne.indexOf("");
int secondListItem = stringOne.indexOf("", firstListItem + 1);
Serial.println("The index of the second list tag in the string " + stringOne + " is " + secondListItem);
// lastIndexOf() gives you the last occurrence of a character or string:
int lastOpeningBracket = stringOne.lastIndexOf('<');
Serial.println("The index of the last < in the string " + stringOne + " is " + lastOpeningBracket);
int lastListItem = stringOne.lastIndexOf("");
Serial.println("The index of the last list tag in the string " + stringOne + " is " + lastListItem);
// lastIndexOf() can also search for a string:
stringOne = "Lorem ipsum dolor sit amet
Ipsem
Quod
";
int lastParagraph = stringOne.lastIndexOf("